189 lines
4.3 KiB
Go
189 lines
4.3 KiB
Go
package diff
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// modified from https://github.com/peter-evans/patience
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import (
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"fmt"
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"strings"
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)
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// DiffType defines the type of a diff element.
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type DiffType int8
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const (
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// Delete represents a diff delete operation.
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Delete DiffType = -1
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// Insert represents a diff insert operation.
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Insert DiffType = 1
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// Equal represents no diff.
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Equal DiffType = 0
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)
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// DiffLine represents a single line and its diff type.
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type DiffLine struct {
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Text string
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Type DiffType
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}
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// typeSymbol returns the associated symbol of a DiffType.
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func typeSymbol(t DiffType) string {
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switch t {
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case Equal:
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return " "
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case Insert:
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return "+ "
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case Delete:
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return "- "
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default:
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panic("unknown DiffType")
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}
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}
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// DiffText returns the source and destination texts (all equalities, insertions and deletions).
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func DiffText(diffs []DiffLine) string {
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s := make([]string, len(diffs))
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for i, l := range diffs {
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s[i] = fmt.Sprintf("%s%s", typeSymbol(l.Type), l.Text)
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}
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return strings.Join(s, "\n")
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}
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// LCS computes the longest common subsequence of two string
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// slices and returns the index pairs of the LCS.
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func LCS(a, b []string, equal func(a, b string) bool) [][2]int {
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// Initialize the LCS table.
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lcs := make([][]int, len(a)+1)
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for i := 0; i <= len(a); i++ {
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lcs[i] = make([]int, len(b)+1)
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}
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// Populate the LCS table.
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for i := 1; i < len(lcs); i++ {
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for j := 1; j < len(lcs[i]); j++ {
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if equal(a[i-1], b[j-1]) {
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lcs[i][j] = lcs[i-1][j-1] + 1
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} else {
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lcs[i][j] = max(lcs[i-1][j], lcs[i][j-1])
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}
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}
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}
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// Backtrack to find the LCS.
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i, j := len(a), len(b)
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s := make([][2]int, 0, lcs[i][j])
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for i > 0 && j > 0 {
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switch {
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case equal(a[i-1], b[j-1]):
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s = append(s, [2]int{i - 1, j - 1})
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i--
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j--
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case lcs[i-1][j] > lcs[i][j-1]:
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i--
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default:
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j--
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}
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}
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// Reverse the backtracked LCS.
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for i, j := 0, len(s)-1; i < j; i, j = i+1, j-1 {
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s[i], s[j] = s[j], s[i]
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}
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return s
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}
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// toDiffLines is a convenience function to convert a slice of strings
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// to a slice of DiffLines with the specified diff type.
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func toDiffLines(a []string, t DiffType) []DiffLine {
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diffs := make([]DiffLine, len(a))
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for i, l := range a {
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diffs[i] = DiffLine{l, t}
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}
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return diffs
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}
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// uniqueElements returns a slice of unique elements from a slice of
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// strings, and a slice of the original indices of each element.
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func uniqueElements(a []string) ([]string, []int) {
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m := make(map[string]int)
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for _, e := range a {
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m[e]++
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}
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elements := []string{}
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indices := []int{}
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for i, e := range a {
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if m[e] == 1 {
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elements = append(elements, e)
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indices = append(indices, i)
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}
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}
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return elements, indices
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}
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// PatienceDiff returns the patience diff of two slices of strings.
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func PatienceDiff(a, b []string, equal func(a, b string) bool) []DiffLine {
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switch {
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case len(a) == 0 && len(b) == 0:
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return nil
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case len(a) == 0:
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return toDiffLines(b, Insert)
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case len(b) == 0:
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return toDiffLines(a, Delete)
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}
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// Find equal elements at the head of slices a and b.
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i := 0
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for i < len(a) && i < len(b) && equal(a[i], b[i]) {
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i++
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}
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if i > 0 {
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return append(
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toDiffLines(a[:i], Equal),
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PatienceDiff(a[i:], b[i:], equal)...,
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)
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}
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// Find equal elements at the tail of slices a and b.
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j := 0
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for j < len(a) && j < len(b) && equal(a[len(a)-1-j], b[len(b)-1-j]) {
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j++
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}
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if j > 0 {
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return append(
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PatienceDiff(a[:len(a)-j], b[:len(b)-j], equal),
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toDiffLines(a[len(a)-j:], Equal)...,
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)
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}
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// Find the longest common subsequence of unique elements in a and b.
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ua, idxa := uniqueElements(a)
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ub, idxb := uniqueElements(b)
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lcs := LCS(ua, ub, equal)
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// If the LCS is empty, the diff is all deletions and insertions.
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if len(lcs) == 0 {
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return append(toDiffLines(a, Delete), toDiffLines(b, Insert)...)
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}
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// Lookup the original indices of slices a and b.
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for i, x := range lcs {
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lcs[i][0] = idxa[x[0]]
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lcs[i][1] = idxb[x[1]]
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}
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diffs := []DiffLine{}
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ga, gb := 0, 0
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for _, ip := range lcs {
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// PatienceDiff the gaps between the lcs elements.
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diffs = append(diffs, PatienceDiff(a[ga:ip[0]], b[gb:ip[1]], equal)...)
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// Append the LCS elements to the diff.
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diffs = append(diffs, DiffLine{Type: Equal, Text: a[ip[0]]})
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ga = ip[0] + 1
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gb = ip[1] + 1
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}
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// PatienceDiff the remaining elements of a and b after the final LCS element.
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diffs = append(diffs, PatienceDiff(a[ga:], b[gb:], equal)...)
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return diffs
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}
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